The heat needed to raise the temperature of 50.0 g of water from 4.5 ⁰C
to 83.0 ⁰C is 16.46KJ
<u>Explanation:</u>
<u>To solve the problem,</u>
<u>we need the value of the water and its given by,</u>
C=4.18 × J/ g ∘
C
To increase the temperature we need m grams of water by n ∘
C
And the formula for the heat is given by, heat= m × n ×specific
heat
<u>q
=
m
⋅
c
.
Δ
T</u>
where q denotes the heat absorbed
m denotes the mass sample
c denotes the specific heat
Δ
T denotes the change in the temperature
Based on the data it is written as,
q= 50.0 g . 4.18 J / g ∘
C (83.0-4.5) ∘
C
Simplifying the equation we get,
<u>q=16406.5 J</u>
Express it in the form of significant figure
16406.5 J . 1 KJ / 10^ 3 J
Solving the equation we get
<u>16.46KJ</u>
The heat needed to raise the temperature of 50.0 g of water from 4.5 ⁰C
to 83.0 ⁰C is 16.46 KJ
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