Equation: 4 + 4x + x²
Maxima: No maximum value from said equation
Minima: x = -2 since that is the only critical point in the equation
Break it off where the triangle goes into a square/ rectangle
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Answer:10 in on left side 13 on top
Step-by-step explanation:
Answer:
427
Step-by-step explanation: