For the first draw, the probability of an ace is ( 4 / 52 ).
Now there are only 51 cards left in the deck.
For the second draw, the probability of a king is ( 4 / 51 ).
The probability of both events is
(4/52) (4/41) = (16/2,652)
Divide top and bottom by 4:
(16/2,652) = <em>4/663</em> . That's <em>choice-C </em>.
No it is not because its more then ten numbers away from the solution of the five tickets
Answer: 20
Step-by-step explanation:
2^2=4
5*2=10
2^2 and 5 would be multiplied
There is a 1/3 chance. Because there are 3 coins