2 years ago

∑from 1to infinity of n^2* e^-2n

1 answer:

Naily [24]2 years ago

3 0

<span>∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768</span>

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