Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?
B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?
Answer:
The frequency change percentage is 9.94%
Explanation:
The frequency shift can be calculated as follows.
=
=9.95 GHz
So the frequency change seen by the detector is 9.95 - 9.05
% difference
= 9.94%
Answer:
118 N
Explanation:
Given mass of the block, m = 4.00kg.
The acceleration of the elevator, a = 3.0 m/s^2.
As elevotar attaced with spring scale and accelerating upward
(block and elevator), so total force
Here, mg is the weight of the block downward direction.
or
substitute the given value, we get
= 117.6 N = 118 N.
Thus, the reading on the spring scale to 3 significant figures is 118 N.
Answer:
Force = 186 N
Explanation:
Torque is the rotational equivalent of linear force. It can be easely calculated using the formula :
Where is a vector that from the origin of the coordinate system to the point at which the force is applied (the position vector), is the applied force.
The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench. By doing this we have that (the magnitud of the position vector) is 35cm.
Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :
Now using the torque formula:
Where is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector , thus :
so the force is approximately 186 N.
C.the acceleration is doubled
Answer:
Gauge Pressure required = 606.258 kPa
Explanation:
Water will not enter the chamber if the pressure of air in it equals that of the water which tries to enter it.
Thus at a depth of 60m we have pressure of water equals
Now the gauge pressure is given by
Applying values we get