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2 years ago

11

What are the coordinates of the image of the point (4,5) after reflecting over the y-axis

1 answer:

NemiM [27]2 years ago

4 0

here is a link to the aneser hope it helps

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Round 7.21 to the nearest whole number.

gtnhenbr [62]

It’s 7...your answer is 7

8 0

2 years ago

Read 2 more answers

Given the graph below, solve the system of equations. <br><br>

goldenfox [79]

Answer:

(4, 3 )

Step-by-step explanation:

Given a system of equations graphically, then the solution is at the point of intersection of the 2 lines.

The lines intersect at (4, 3 ) ← solution

3 0

2 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

2 years ago

Difference between normal of parallel planes and perpendicular planes

Alex787 [66]

Parallel planes never touch

7 0

2 years ago

Graph the linear inequality: 2x + 3y = 12, by creating a t-chart to plot the points. Shade by

Crazy boy [7]

Answer:

See explanation

Step-by-step explanation:

Assuming the given inequality is $2x+3y\le12$

Then the corresponding linear equation is $2x+3y=12$

When x=0, we have $2*0+3y=12$

$\implies 3y=12\implies y=4$

When y=0, we have $2x+3*0=12$

$\implies 2x=12\implies x=6$

The T-table is:

<u>x | y</u>

0 | 4

6 | 12

We plot this points and draw a solid straight line as shown in the attachment.

Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.

$2*0+3*0\le12$

$0\le12$ ....This is true so we shade the lower half plane as shown in the attachment.

6 0

2 years ago