Ask question

Ask question

All categories

2 years ago

11

robs tablet is fully charged he uses 1/12 of the charge playing games,5/12 of the charge reading, and 3/12 completing homework W

hat of the charge remains on robs tablet

2 answers:

frosja888 [35]2 years ago

7 0

3/12
1/12+ 5/12+ 3/12= 9/12
12/12-9/12=3/12

elena55 [62]2 years ago

7 0

I think it is 3/12 in not fully sure though

You might be interested in

Find values of x and y. state which theorem(s) you used<br><br>please help

alexira [117]

I believe X and Y are also 61°! Report me if I am wrong!

3 0

2 years ago

The lengths of angles given represent the sides or angles of a triangle.

Dafna1 [17]

Answer:

C.

Step-by-step explanation:

Comparing the sides: 20 = 12 + 8.

The largest side must be less than the sum of the other 2 sides for there to be a triangle.

No triangle can have these dimensions.

4 0

2 years ago

In the diagram below, AB and BC are tangent to O. What is the measure of angle B?<br>APEX

Whitepunk [10]

option C <B = 54° ( answer is attached )

4 0

2 years ago

Read 2 more answers

Please help!!!!!

vampirchik [111]

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

$ax^2+bx+c=0$

Dividing the equation by a, we get

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

Put $\frac{c}{a}$ on the other side,

$x^2+\frac{b}{a}x=\frac{-c}{a}$

Add $(\frac{b}{2a})^2$ on both the sides,

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

completing the square, we have

$(x+\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

Now, solving for x,

$x+\frac{b}{2a}={\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

$x=\frac{-b}{2a}{\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

Multiply right side by $\frac{2a}{2a}$ ,

$x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}$

which is the required quadratic formula.

8 0

2 years ago

Read 2 more answers

A rectangular park measures 300ft by 400ft. A sidewalk runs diagonally from one corner to the opposite corner. Find the lunch of

saveliy_v [14]

When we are given a line cutting diagonally from one corner of a rectangle to the opposite corner, we are given two triangles.

300ft
____
| /|
| / |
| / |
| / |400ft
| / |
| / |
|/ |
-------

*not to scale

Now, using the right-angle trigonometry rule, we can find the hypotenuse (the diagonal line) which represents the footpath.

a^2 + b^2 = c^2

{where a is one side length, b is another side length, and c is the hypotenuse}

Thus, we make c the subject of the equation and substitute the other known values:

c^2 = 400^2 + 300^2
= 160,000 + 90,000
= 250,000

Now we move the 'squared' (^2) from the left hand side to the right hand side. When moving it across the equal sign (=) the result becomes the 'root' of itself:

c = _/250,000
= 500

Therefore, the length of the diagonal path is 500ft.

5 0

2 years ago