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2 years ago

Write the equation in logarithmic form 8^x=64

Mathematics

1 answer:

Alona [7]2 years ago

8 0

Step-by-step explanation:

8^x= 64

8²= 64

In logarithmic form,

log(base 8) 64= 2

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Your part time job pays you $14/h. You work approximately 12 hours/week.

kirill115 [55]

Answer:

BOX 1 = 672.00

(14 * 12 = 168

168 * 4 = $ 672 )

2. BOX 2 = 282.95

(Cell phone= $45 A MONTH

Eating outside = $50 A MONTH

12 .50 * 4 = 50 (4 WEEKS A MONTH )

Transportation = 131.2 A MONTH

32.80 * 4 = 131.2 (4 WEEKS A MONTH )

Movie = $16.75 A MONTH

Charity = $ 40 A MONTH

10 * 4 (4 WEEKS A MONTH )

 MONTHLY EXPENSE  = 45 + 50 + 131.2 + 16.75 + 40

 MONTHLY EXPENSE  = 282.95 )

3. BOX 3 = 389.05

Money that can be saved = Monthly income - Monthly expense

Money that can be saved = 672 - 282.95

= 389.05

<h2>please give brainliest </h2>

4 0

2 years ago

What is y=4x^2-9x+1 in vertex form

Anna11 [10]

Answer:

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

Step-by-step explanation:

$y = 4x^2 - 9x + 1$

You need to complete the square on the right side.

$y = (4x^2 - 9x) + 1$

$y = 4(x^2 - \dfrac{9}{4}x) + 1$

$y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

3 0

2 years ago

Can please answer these 3 questions

kupik [55]

So it would be 32 lol if

6 0

2 years ago

Given f(x) =

sergejj [24]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = \left\{ \begin{array}{ll} 2\cos(\pi x) \text{ for } x \leq -1 \\ \\ \displaystyle \frac{2}{\cos(\pi x)}\text{ for } x > -1 \end{array} \right.$

And we want to find:

$\displaystyle \lim_{x\to -1}f(x)$

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

$\displaystyle \lim_{x\to-1^-}f(x)$

Since we are approaching from the left, we will use the first equation:

$\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)$

By direct substitution:

$=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2$

Right-Hand Limit:

$\displaystyle \lim_{x\to -1^+}f(x)$

Since we are approaching from the right, we will use the second equation:

$=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}$

Direct substitution:

$\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2$

So, we can see that:

$\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2$

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

$\displaystyle \lim_{x \to -1}f(x)=-2$

Our answer is A.

8 0

2 years ago

$12.50 for 5 ounces

iragen [17]

Answer:

45 copies per minute

Look at drawing for an explanation

6 0

2 years ago

Write the equation in logarithmic form 8^x=64​

Write the equation in logarithmic form 8^x=64