What is the interquartile range for this data set? 9, 17, 3, 26, 9, 15, 7, 20, 5, 12, 22
stepan [7]
23 because you subtract your highest number with your lowest number
Answer: -1/2
Step-by-step explanation:
Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
0.875
Step-by-step explanation:
look at the fraction as a division problem
8÷7
