Answer:
Given A triangle ABC in which
∠C =90°,∠A=20° and CD ⊥ AB.
In Δ ABC
⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]
⇒20° + ∠B + 90°=180°
⇒∠B+110° =180°
∠B =180° -110°
∠B = 70°
In Δ B DC
∠BDC =90°,∠B =70°,∠BC D=?
∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]
90° + 70°+∠BC D =180°
∠BC D=180°- 160°
∠BC D = 20°
In Δ AC D
∠A=20°, ∠ADC=90°,∠AC D=?
∠A + ∠ADC +∠AC D=180° [angle sum property of triangle]
20°+90°+∠AC D=180°
110° +∠AC D=180°
∠AC D=180°-110°
∠AC D=70°
So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°
To find the slope you use the slope formula y2-y1 / x2-x1. So use two point on the line we will make ours (1,2) and (3,4). Substitute to make 4-2 / 3-1 = 1/1 so using the rise over run method. The line rises up one and runs by one. The slash mark means divide, it's easiest in a fraction.
Also if you come across the equation y=mx+b, m is the slope and b is the y-intercept, this is called slope intercept formula.
Answer:
I think the answer is twenve
Answer:
No its not
Step-by-step explanation:
When 42(x + 14y) is simplified:
42(x + 14y)
Expand and remove the brackets. Remember brackets mean to multiply.
42*x
42x
42*14y
588y
42x+588y
Therefore 42x-56 is NOT EQUIVALENT to 42(x + 14y) but is equivalent to 42+588y