|x+2|-3=9 please help!!! Solve twice!!! Two answers!!!
2 answers:
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Answer:
a < -1
Step-by-step explanation:
Okay, so we are given this equation:
t(x) = ax^5 + 2
Lets plug in -2 as x and see what happens.. t(x) can be 66..
= 66
-32a + 2 = 66
-32a = 64
a = -2
A is less than -1,
a < -1
Answer:
x = 105°
Step-by-step explanation:
Question :
You can use cross multiplication to solve this.
Let us solve now
12 × x = 35 × 36
12x = 1260
Divide both sides by 12.
x = 105°
Hope this helps you :-)
Answer:
D.)
Step-by-step explanation:
The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts. You can graph the function and see when the graph crosses the x-axis or solve for the x-values. I will solve it via factoring and so:
Multiply the outer coefficients, in this case 1 and 6, and 1×6=6. Now let's think about all the factors of 6 we have: 6×1 and 2×3. Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5? Actually we can say 6-1=5 and 2+3=5. Let's try both.
First let's use 6 and -1 and so:
Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.
Now let's try 2 and 3 and so:
Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:
Case 1:
Case 2:
So your zero's are when x=-2 and x=-3.
D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.
~~~Brainliest Appreciated~~~