The circumference of a circle -
The radius is
10 in.
The two limits when x tends to zero are:
<h3 /><h3>How to get the limits when x tends to zero?</h3>
Notice that we have a jump at x = 0.
Then we can take two limits, one going from the negative side (where we will go along the blue line)
And other from the positive side (where we go along the orange line).
We will get:
Notice that the two limits are different, that means that the function is not a continuous function.
If you want to learn more about limits:
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Answer:
y = 4x + 1
Step-by-step explanation:
y = mx + b
b = y-intercept
From the graph we see that b = 1
m = slope
Start at (0, 1). Go up 8 units. Rise = 8. Go right 2 units. Run = 2.
slope = rise/run = 8/2 = 4
y = 4x + 1
Answer:
720
Step-by-step explanation:
60 minutes in a hour. So add 30 for each 20 minutes so it would be 90 an hour so multiply 90 by 8
Answer:
3) 67/441
Step-by-step explanation:
Comparing the given equation to the expressions you need to evaluate, you find there might be a simplification.
3x² +5x -7 = 0 . . . . . given equation
3x² +5x = 7 . . . . . . . add 7
x(3x +5) = 7 . . . . . . . factor
3x +5 = 7/x . . . . . . . . divide by x
Now, we can substitute into the expression you are evaluating to get ...
1/(3α +5)² +1/(3β +5)² = 1/(7/α)² +1/(7/β)² = (α² +β²)/49
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We know that when we divide the original quadratic by 3, we get
x² +(5/3)x -7/3 = 0
and that (α+β) = -5/3, the opposite of the x coefficient, and that α·β = -7/3, the constant term. The sum of squares is ...
α² +β² = (α+β)² -2αβ = (-5/3)² -2(-7/3) = 25/9 +14/3 = 67/9
Then the value of the desired expression is ...
(67/9)/49 = 67/441