All categories

2 years ago

What mass of oxygen reacts with 3.6 g of magnesium to form magnesium oxide?

Chemistry

1 answer:

levacccp [35]2 years ago

3 0

Answer is: the mass of the oxygen is 2.37 grams.

Balanced chemical reaction: 2Mg + O₂ → 2MgO.

m(Mg) = 3.6 g; mass of magnesium.

n(Mg) = m(Mg) ÷ M(Mg).

n(Mg) = 3.6 g ÷ 24.3 g/mol

n(Mg) = 0.149 mol.; amount of the magnesium.

n(O₂) = ?

From chemical reaction: n(Mg) : n(O₂) = 2 : 1.

n(O₂) = n(Mg) ÷ 2.

n(O₂) = 0.149mol ÷ 2.

n(O₂) = 0.075 mol; amount of the oxygen.

m(O₂) = m(O₂) · M(O₂).

m(O₂) = 0.075 mol · 32 g/mol.

m(O₂) = 2.37 g; mass of the oxygen.

You might be interested in

Help with both questions ASAP PLEASE

Step2247 [10]

Mg reducing agent and Cu oxidising agent.

6 0

2 years ago

Can oxygen ever have more then 8 protons? why or why not

EastWind [94]

No because it changes its composition to ozone

3 0

2 years ago

Arachidonic acid and pge1 are both carboxylic acids with atoms. the differences are that arachidonic acid contains and no other

hichkok12 [17]

Answer:
Arachidonic Acid and PGE₁ are both carboxylic acids with Twenty Carbon atoms. The differences are that Arachidonic acid contains Four cis Double Bonds and no other functional groups, whereas PGE₁ has One Trans Double Bond, Two Hydroxyl and One Ketone Functional Groups.. In addition, a part of the PGE₁ chain forms a Five Membered Ring.

Structures of Both Arachidonic Acid and PGE₁ are shown Below,

8 0

2 years ago

Round the following number to four figures: 45.4673

zhenek [66]

This says four figures. The 4 figures you should use are 4546 with a peek at 7 to see what effect it will have on the 4 main figures.

45.467 rounds to 45.47

You round the 4th figure up one. You are not concerned about the decimal places in this question.

7 0

2 years ago

Read 2 more answers

Determine the percent water in MgSO4*7H20?

Semmy [17]

Answer:

$\% H_2O=51.2\%$

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

$MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol$

Thus, the percent water is:

$\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\$

So we plug in to obtain:

$\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%$

Best regards!

5 0

2 years ago