Answer:
(-8.5,9)
Step-by-step explanation:
((-8+(-9))/2=-8.5
(7+11)/2=9
(-8.5,9)
We are dealing here with a uniform distribution ranging from 0 to 30 minutes. We need to calculate the probability that the unreliable bus will arrive before the reliable one. This probability is the area under the uniform distribution "curve" from 0 to 10 minutes. This constitutes 1/3 of the entire unform distr. curve. So the probability that the unreliable bus will arrive before the reliable one is 1/3, or 0.33. The probability that it will arrive AFTER the reliable bus is 2/3, or 0.67.
Answer:
x = 18
Step-by-step explanation:
5/6x = 15
Multiply each side by 6/5 to isolate x
6/5 * 5/6 x = 15 *6/5
x = 15/5 *6
x =3*6
x = 18
Answer:
See below
Step-by-step explanation:
sf = s0 + v0 t + 1/2 at^2
1 + (-3)t + 1/2 (.2t) t^2 ( weird acceleration value)
s = 1 -3t + .1 t^3 You will need a 't' value to determine the position