Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
256.
The coefficient of just the y term would be 256 because the entire expanded equation looks like this:
y^4+16y^3+96y^2+256y+256
Answer: m∠RQS=104° and m∠TQS=76°
Step-by-step explanation:
Answer:
check: 50+160+130+20 = 360
50:160 = 5 : 16
Step-by-step explanation:et the smaller of the unknown angles be 5x and the larger of the two be 16x
so 130+20+5x+16x = 360
21x = 210
x = 10
so the two missing angles are 50° and 160°
check: 50+160+130+20 = 360
50:160 = 5 : 16
Answer:
The answer is A :))
Step-by-step explanation: