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2 years ago

15

Why is it difficult to determine earth's inner structure

1 answer:

Lesechka [4]2 years ago

5 0

It is hard because we can't get past the crust, Our machines will burn up at the mantle and so will we. The layers go: crust, mantle, outer core, inner core.

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What do the three types of mixtures have in common? <br> (colloid, solution, suspension)

trasher [3.6K]

Answer:

A colloid is a heterogeneous mixture in which the dispersed particles are intermediate in size between those of a solution and a suspension. The particles are spread evenly throughout the dispersion medium, which can be a solid, liquid, or gas.

Explanation:

6 0

2 years ago

If 21.3 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 297 Kelvin and 1.40 atmosph

Gnoma [55]

Hope it helped you.

4 0

2 years ago

PLEASE CAN SOMEONE EXPLAIN this FOR ME WHAT IS RADIOACTIVE ISOTOPES AND ANSWER THIS QUETION? A nitrogen atom has 7 protons and m

zalisa [80]

Answer:

$\frac{15}{7}N$

Explanation:

We already know that the mass number of an atom is the sum of the number of protons and the number of neutrons.

So, the mass number of this isotope is;

Number of protons = 7

Number of neutrons = 8

Mass number = 7 + 8 = 15

Hence, the isotope is;

$\frac{15}{7}N$

3 0

2 years ago

Which statement best describes the work and energy in these examples?

kari74 [83]

Answer:

The gas and food are examples of energy.

Explanation:

The reason why is that food is energy as proteins and electrolytes. Gas is a energy of fossil fuels.

3 0

2 years ago

The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an

ser-zykov [4K]

Answer:

$24540\frac{mg}{m^3}$

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

$\frac{3L\ CO}{L\ gas}$

By using the ideal gas equation we compute the density of CO:

$\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L$

Then we apply the conversion factors as follows:

$=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}$

Regards.

4 0

2 years ago