Answer:
0.800 m/s²
Explanation:
First, calculate the angular acceleration:
ω = αt + ω₀
6.00 rad/s = α (3.00 s) + 0 rad/s
α = 2.00 rad/s²
Now calculate the angular velocity at t = 2.00 s:
ω = αt + ω₀
ω = (2.00 rad/s²) (2.00 s) + 0 rad/s
ω = 4.00 rad/s
Calculate the linear velocity:
v = ωr
v = (4.00 rad/s) (0.0500 m)
v = 0.200 m/s
Finally, calculate the centripetal acceleration:
a = v² / r
a = (0.200 m/s)² / (0.0500 m)
a = 0.800 m/s²
Answer:
t = 2 v₀ / g
Explanation:
For this projectile launch exercise we use the displacement equations
x = vox t
y = y₀ + t - ½ g t²
As it is launched horizontally the vertical velocity is zero and the point of origin of the coordinate system is here, so y₀ is zero.
x = v₀ t
y = ½ g t²
They ask us for the time for which
x = y
vo t = ½ g t²
t = 2 v₀ / g
The provided question is not correct as, there is more than one options are correct, however the explaining every correct option -
Answer:
The correct answer are - silver, copper and aluminium all three used as fuse material.
Explanation:
A safety device in any electric circuit of that prevents the electric system in case of short circuit by breaking the connection of electric system or circuit termed as the Fuse or fuse element. Normally the fuse are made up of wire or element of material that are low in melting point and high in resistance.
Zinc, lead, tin, silver, copper, aluminium, and alloy of tin and alloy are used as fuse element or material for their low melting point and high resistance these are easily breaks the electric path in case of short circuit.
Answer:
Inorganic matter
Explanation:
These are things like air, water, rocks, soil and metals.
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Gravity causes falling objects to accelerate.