Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
=7/6
Step-by-step explanation:
Join 4/3=1:7/3
7/3/2
Apply the fraction rule:=
7/3x2
Multiply the numbers=
7/6
For number 1 I think it is 1.02n because I added the like terms together
Answer:
point is (13/4 , 17/2)
Step-by-step explanation:
Let (x1,y1) and (x2,y2) be the end points of a line segment, 'A' is the point on the line segment such that A divides the line segment in the ratio p : q then the coordinates of A (x,y) is given by,
x = x1 + p/w(x2 - x1) and y= y1 + p/w(y2 - y1) where w = p+q
It is given that,
Point A is located at (4, 8) and point B is located at (14, 10) .
Let P be the point on AB such that P divides AB in the ratio 1:3
<u>Find the coordinates of P(x,y)</u>
w = 1+3 = 4
x = x1 + p/w(x2 - x1) = 4 + 1/4(14 -4) = 4 + 10/4 =13/4
y= y1 + p/w(y2 - y1) = 8 + 1/4(10 - 8) = 8 + 1/2 = 17/2
point is (13/4 , 17/2)
