Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2 and the probability of allele B in a
gamete is 1/2, then the probability that both A and B are in the same gamete is
1 answer:
Answer:
P(A and B) = 1/4
Step-by-step explanation:
Since A and B are not linked. The event is said to be independent events:
Therefore;
P(A and B) = P(A) × P(B)
Where; P(A and B) is the probability that both A and B are in the same gamete.
P(A) = 1/2 => Probability of allele A in the gamete
P(B) = 1/2 => Probability of allele B in the gamete
Thus,
P(A and B) = P(A) × P(B) = (1/2) * (1/2) = 1/4 = 0.25.
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