Given:
One midsegment of an equilateral triangle.
To find:
The ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths.
Solution:
All sides of an equilateral triangle are same.
Let a be the each side of the equilateral triangle.
Length of the midsegment is equal to the half of the non included side or third side.
The sum of two side is
Now, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is
Therefore, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is 1:4.
Answer:0.5
Step-by-step explanation: If you flip the numbers and the continue to multiply them across and then divide them after you should get 0.5
Answer:
C) -0.71m/s²
Step-by-step explanation:
V = V0 + at
V = final veloctiy
V0 = Initial velocity
a = acceleration
t = time
3 = 9 + a7
-5 = a7
= a
a ≅ -0,71
Answer:
The measure of the third arc is
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
----> equation A
-----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z