Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
x=0, y=2. (0, 2).
Step-by-step explanation:
3x+2y=4
8x-3y=-6
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3(3x+2y)=3(4)
2(8x-3y)=2(-6)
-----------------------
9x+6y=12
16x-6y=-12
----------------
25x=0
x=0/25
x=0
3(0)+2y=4
0+2y=4
2y=4-0
2y=4
y=4/2
y=2
Answer:
The scale used is 1: 10,000 cm.
Step-by-step explanation:
Given that the length of a pool 2 km long is represented on a map with a length of 20cm, to determine what is the map scale used the following calculation must be performed:
2 km = 2,000 m
1m = 100cm
2,000 x 100 = 200,000
20: 200,000
10: 100,000
1: 10,000
Thus, the scale used is 1: 10,000 cm.
Answer:
IT is 41.5 heres the steps
Step-by-step explanation:
first step 21 divided by 2 = 10.5
Then you do 10.5 + 1 = 11.5
then you do 11.5 times 5 = 57.5
Then 2 times 2 times 2 times 2= 16
then 16 - 57.5 = 41.5 is your answer