Answer:
The right answer is 8.9 x 10^-3 M/min
Explanation:
A → B
-d [A]/dt = K [A]
ΔA/Δt = - (C2 -C1)/t2 - t1
= - (0.11 - 0.91)/90
= 8.9 x 10^-3 M/min
Answer:
30.96 m
Explanation:
If the particle has a lifetime of 129 ns as measured by observer A, and has a speed of 0.8c as measured by observer A, the distance between the markers will be:
d = v * Δt
v = 0.8*c = 0.8 * 3e8 = 2.4e8
Δt = ζ = 129 ns = 1.29e-7 s
d = 2.4e8 * 1.29e-7 = 30.96 m
This is the distance as measured by observer A.
Answer:
B
Explanation:
Is the equilibrium stable or unstable for the third charge
Answer:
Correct, is there another part to the question?
3.13 m/s2
.
the formula for acceleration is as follows:
force/mass = acceleration
-
so 25/8 = 3.13