It's the same amount each month, for a year. So:
total money ÷ times money was taken out= how much has been taken out.
$600÷12=50
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
Solution given:
<u>B: 9x - 4/x^2 - 4</u>
Step-by-step explanation:
.k
Answer:
2300
Step-by-step explanation:
We are given that
Out of 200 , four ducks are tagged.
We have to find the number of ducks in the preserve if 46 ducks are tagged.
Let x be the number of ducks in the preserve.
If number of tagged ducks increases then number of preserved ducks also increases.It is in direct proportion.
According to question
x=2300