Answer:
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Step-by-step explanation:
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A=3,500×(1+0.0485÷4)^(4×11)
A=5,947.99
6000=3500(1+0.0485/4)^4t
Solve for t to know the time needed to reach 6000
Time=11.2
So the time needed is 11 years and 2 months
Cost of fuel = 30% of $400 000 = 30/100 x 400000 = $120 000
Fuel amount = $120 000/$1.5 = 80 000 liters
new cost of fuel = 80000 x $1.6 = $144 000
increase in cost = 144000 - 120000 = $24000
So the increase in petrol price increases the operating cost by $24000
