Answer:
0.6x < 12.5
x < 20.83 days
Step-by-step explanation:
Diego's family car holds 14 gallons of fuel. Each day the car uses 0.6 gallons of fuel. A warning light comes on when the remaining fuel is 1.5 gallons or less. Write an inequality that represents the number of days Diego's father can drive the car without the warning light coming on. Explain each part of your inequality
Car fuel capacity = 14 gallons
Fuel capacity that shows warning light = 1.5 gallons
Fuel capacity without warning light = Car fuel capacity - Fuel capacity that shows warning light
= 14 gallons - 1.5 gallons
= 12.5 gallons
Fuel used per day = 0.6 gallons
Let
x = number of days Diego's father can drive the car without the warning light coming on
The inequality is
0.6x < 12.5
Solve for x
x < 12.5/0.6
x < 20.83 days
The problem statement is not clear regarding which money is invested. We will assume it is the 80% of $8750 that is set aside for future education. That amount is
... 0.80 × $8750 = $7000
If x represents the amount invested at 7%, then the total interest earned is
... (7000 -x)×4% + (x)×7% = 420
... 280 +0.03x = 420
... x = 140/0.03 ≈ 4666.67
$4666.67 was invested at 7%.
$2333.33 was invested at 4%.
1. Sry, I am confused by this one
2. Positive Integer factors of 196 = 2, 4, 7, 28, 196/2, 2, 7, 7, leaves it with no remainder.
3. Neither
4. Prime
5. Composite
6. 80, 96, 112 (pattern: add 16 each time)
7. 29, 36, 38 (pattern: add 7, add 2 and so on)
Hope this helped!!
Also, can I pls, pls, pls have brainliest? I need about 100 more points and 1 brainliest to lvl up to Ace!!
