Answer:
2.5 half-lives
Step-by-step explanation:
Find 
in 
given 
is the amount after the time 
, 
`is the initial amount, is the half-life
We know that after half-life there will be twice less the initial quantity:
.
Simplifying gives 
Plugging this into the initial equation, we obtain that 
or 
Finally, just plug in the given values and find the unknown one.
From 
, we have that 
= 
So you should get: 
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So 2 real solutions
just write 2 factors and expand
(x-3)(x-4)=0
x^2-7x+12=0
discriminant is when you have b^2-4ac
so subsitute
ax^2+bx+c=0
a=1
b=-7
c=12
-7^2-4(1)(12)
49-48=1
discriminant=1
one real solution would be
(x-1)(x-1)=0
x^2-2x+1=0
discriminant=-2^2-4(1)(1)=4-4=0
discriminant=0
no real solutions has the discriminant less than zero
let's say that b=1 and c=20 and a=1
basically, we need a set of numbers where b^2 is less than 4acso
1^2-4(1)(20)=1-80=-79
then we subsitute
x^2+x+20=0
We have to find the greatest possible number of each type of flower
( pansies and daisies ) in each row.
We have to find the GCF for 27 and 36.
27 = 9 * 3
36 = 9 * 4
So : GCF ( 27, 36 ) = 9
We will have 9 pansies in 3 rows and 9 daisies in 4 rows.
Answer:
The greatest possible number of pansies in each row is 9.
" the product " means multiply
the product of 8 and a number Q is at least 32...
8Q > = 32 (thats greater then or equal to)
