Latus rectum is the line segment that passes through the focus, is perpendicular to the axis, and has both endpoints on the curve.
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Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration: , where is the final velocity in a direction after the acceleration is applied, is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
- <em>Then for the x direction</em> it is known that the initial velocity is 5320 m/s, the acceleration (the applied by the engine) in x direction is 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then:
- In the same fashion, <em>for the y direction</em>, the initial velocity is 0 m/s, the acceleration in y direction is 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction:
Answer:
in the ordered pair; ( x = 27/4 , y = 1/4 )
Step-by-step explanation:
Given that:
The system of the equation shown below is:
-2x - 14y = 10
2x + 2y = 14
We are to use the elimination method to determine the ordered pair.
From the above equation:
-2x - 14y = 10 --- (1)
2x + 2y = 14 --- (2)
Add both equation 1 and 2 together in order to eliminate x, then we can solve for y first.
-2x - 14y = 10
<u> 2x + 2y = 14 </u>
<u> 0 - 16y = -4 </u>
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- 16 y = - 4
divide both sides by - 16, Then:
-16y /-16 = -4/-16
y = 1/4
Since y = 1/4, Then from equation (2), x will be :
2x + 2y = 14
2x + 2(1/4) = 14
2x + 1/2 = 14
2x = 14 - 1/2
2x = 13.5
x = 13.5/2
x = 27/4
Thus, in the ordered pair; ( x = 27/4 , y = 1/4 )