Answer:
it will take 36.12 ms to reduce the capacitor's charge to 10 μC
Explanation:
Qi= C×V
then:
Vi = Q/C = 30μ/20μ = 1.5 volts
and:
Vf = Q/C = 10μ/20μ = 0.5 volts
then:
v = v₀e^(–t/τ)
v₀ is the initial voltage on the cap
v is the voltage after time t
R is resistance in ohms,
C is capacitance in farads
t is time in seconds
RC = τ = time constant
τ = 20µ x 1.5k = 30 ms
v = v₀e^(t/τ)
0.5 = 1.5e^(t/30ms)
e^(t/30ms) = 10/3
t/30ms = 1.20397
t = (30ms)(1.20397) = 36.12 ms
Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.
Answer:
Acceleration,
Explanation:
It is given that,
Speed of electron,
Charge on an electron,
Mass of electron,
Magnetic field,
Magnitude,
Magnetic force is given by :
Also, F = ma
So, the acceleration of the electron is . Hence, this is the required solution.
Power = Work Done / Time taken
Where Work Done is Joules, and Time is in Seconds, Power is in Watts
= 2400 J / 6 seconds
= 400 Watts
The power output is 400 Watts.
Answer:
friction help to slow motion in other word it oppose motion, but in a frictionless environment object would move with difficult stopping point.
The "generational change" approach to managing innovation assumes that innovation is a predictable process made up of a series of steps and that compressing the time ittakes to complete those steps can speed up innovation.