Answer:
Changing g(x) to this form: a(x-h) + k, we have:
g(x) = 4 (x+3)^2 - 6
Comparing this to the original equation, f(x) = x^2, we have the following transformations:
The graph is widened.
The graph is shifted left 3 units.
Answer:
y=5x-10
Step-by-step explanation:
y+10=5x
y=5x-10
Answer:
take lowest common factor
Step-by-step explanation:
Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Step-by-step explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:
If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:
The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.