Answer:
6,41 min
Explanation:
For the reaction:
A → products
kinetics first-order reaction law is:
ln[A] = ln[A]₀ -kt
Where [A] is concentration of reactant, [A]₀ is initital concentration of reactant, k is rate constant and t is time.
If the concentration of A is 6,25% you can assume:
[A] = 6,25; [A]₀= 100. Replacing:
ln(6,25) = ln(100) -7,20×10⁻³s⁻¹t
-2,7726 = -7,20×10⁻³s⁻¹t
385s = t
In minutes:
385s×
= <em>6,41 min</em>
<em></em>
I hope it helps!
It is appropriate to form double or triple bonds in a Lewis structure when four or six electrons are shared.
A Lewis structure is a representation of a molecule using dots to show the valence electrons in the molecule. This dots are shown around the symbols of the elements.
However, in instances where four or six electrons are shared between bonding atoms, a double or triple bond is used. A double bond means that four electrons are shared. A triple bond means that six electrons are shared.
Learn more: brainly.com/question/1527403
The solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.
<h3>
Dissociation reaction of Ca(OH)2</h3>
The dissociation reaction of Ca(OH)2 is given as follows;
Ca(OH)₂ ⇄ Ca²⁺ + 2OH⁻¹
x 2x
Concentration of Ca²⁺ = 0.469 M
Ksp = [x][2x]²
ksp = (0.469)(2x²)
ksp = 4(0.469)x²
ksp = 1.876x²
4.96 x 10⁻⁶ = 1.876x²
x² = (4.96 x 10⁻⁶)/(1.876)
x² = 2.643 x 10⁻⁶
x = √(2.643 x 10⁻⁶)
x = 1.626 x 10⁻³ M
x = 1.626 mM
Thus, the solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.
Learn more about solubility here: brainly.com/question/23946616
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The pH meter measure the concentration of the hydrogen(+) ion, and the concentration of Hydroxide(-). Hydrogen is acidic, Hydroxide is basic.
The answer is D.
