Answer:
dude your math period is way too long
Step-by-step explanation:
6x^2y^3/2x-2
=6x^2y^3/2 (x-1)
=3x^2y^3/(x-1)
Answer:
its down 1 over 2 each time
Given:
wild turkey ; 12 in the first hour and cumulative number increases by 40% per hour
white-tail deer ; 18 in the first hour and 10 deer each hour after that.
wild turkery: 12 * (1.40)^n-1 ; n is the number of hour
white-tail deer: 18 + 10^n-1 ; n is the number of hour
n wild turkey white-tail deer
1 12 18
2 17 28
3 24 38
4 33 48
5 46 58
6 65 68
7 90 78
It would be hour 7 after sunrise that the cumulative count of the turkeys first exceed the cumulative count of the deer.
Answer:
x ≈ 2.91644500708
Step-by-step explanation:
The equation can be simplified to ...
2(4^x) +4(4^x) = 342
6(4^x) = 342
4^x = 57
Taking logarithms, we get ...
x = log₄(57) = log(57)/log(4)
x ≈ 2.91644500708
