Answer:
Probability of stopping the machine when is 0.0002
Probability of stopping the machine when is 0.0013
Probability of stopping the machine when is 0.0082
Probability of stopping the machine when is 0.0399
Step-by-step explanation:
There is a random binomial variable that represents the number of units come off the line within product specifications in a review of Bernoulli-type trials with probability of success . Therefore, the model is . So:
Probability of stopping the machine when is 0.0002
Probability of stopping the machine when is 0.0013
Probability of stopping the machine when is 0.0082
Probability of stopping the machine when is 0.0399
Finding the sample size for estimating a population proportion.
The formula is:
n = (z/m)^2 p~(1−p~)
where:
Z is the z value of the confidence level where 95% is equal to 1.96
M is the margin of error where 0.05
And p~ is the estimated value of the proportion where it is 0.50
Solution:
n = (1.96/0.05)^2 (0.5) (1-0.5)
= 1.536.64 (0.5) (0.5)
= 768.32 (0.5)
= 384.16
This is the minimum sample size, therefore we should round it up to 385. The answer is letter c.
-2(3x - 9) + 5x = -10
-6x + 18 + 5x = -10
-6x + 5x = -10 - 18
-x = -28
x = 28 <===
Answer:
2.20
Step-by-step explanation:
2.20
Answer:
210
Step-by-step explanation:
so the four Smallest Primes
:
2, 3, 5, 7
When the number is Divided by 2, 3, 5 & 7 Leaves remainder 1
so N = 2a + 1
N = 3b + 1
N = 5c + 1
N = 7d + 1
-> N - 1 = 2a = 3b = 5c = 7d
N - 1 = 2 * 3 * 5 * 7
-> N - 1 = 210
-> N = 211
Next N - 1 = 2(210)
-> N - 1 = 420
-> N =421
Difference = 421 - 211 = 210