These questions can be daunting at first, but they're pretty simple to solve.
First, we need to establish a common denominator. We have 2 / 3, 1 / 4, and
-4 / 3. The least common denominator we can get is by multiplying 4 and 3 together to get 12. So we will change the denominator as follows;
2 / 3, 1 / 4, -4 / 3 = 8 / 12, 3 / 12, -16 / 12
Now we can put these back into the equation.
8/12x + 3/12 = -16/12
8x + 3 = -16
It's simple math from here on out, but I'll show the process. What we can basically do now is take away the denominator because it doesn't matter now that it's common.
Subtract 3 from both sides. Now we have 8x = -19
Dividing by 8 on both sides of the equation will get you your answer.
x = -19/8
Hope this helps!
Answer:
where does the normal line to the ellipse x2−xy y2=3 at the point (−1,1) intersect the ellipse for the second time?
Step-by-step explanation:
they Juan Carlos y los sigo pliss yyi de bvz
<span>hmmm: g maps x onto 3-2sin(x) for all x from 0 to A degrees
g(x) = 3-2sin(x)
the inverse would have to be arcsin (3-x)/2, which only has a radian output between -pi and pi i believe. but this is just from memory</span>
Answer:
red question= 8.5 yellow question=4.25
Step-by-step explanation: