Given function : 3x−6y=12.
We are given x : −2 0 4.
We need to find the values of y's for x=-2, x=0 and x=4.
Plugging x=-2 in the given equation, we get
3(-2)−6y=12
-6 - 6y = 12.
Adding 6 on both sides, we get
-6+6 - 6y = 12+6
-6y = 18.
Dividing by -6 on both sides, we get
y= -3.
On the same way, plugging x=0.
3(0)−6y=12
-6y =12.
y=-2.
Plugging x=4,
3(4)−6y=12
12 -6y = 12.
Subtracting 12 on both sides.
12-12 -6y = 12-12
-6y=0
y=0.
Therefore,
<h3>x −2 0 4</h3><h3>y -3 -2 0</h3>
Answer:
no solution
Step-by-step explanation:
5x - 8(x + 5) = 6 - 3x
Remember to follow PEMDAS. Note the equal sign, what you do to one side, you do to the other.
First, distribute -8 to all terms within the parenthesis
-8(x + 5) = (-8)(x) + (-8)(5) = -8x - 40
5x - 8x - 40 = 6 - 3x
Isolate the variable (x). Add 3x & 40 to both sides
5x - 8x (+3x) - 40 (+40) = 6 (+40) - 3x (+3x)
5x - 8x + 3x = 6 + 40
Simplify. Combine like terms
(5x - 8x + 3x) = (6 + 40)
0 = 46 ; False 0 ≠ 46 ∴ no solution is your answer
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Answer:
try A!
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hope this helps!