Answer:
pressure of water will be 49.7 atm
Explanation:
given data
pressure = 30 psi = 2.04 atm
water = 2 pound = 907.18
mole of water vapor = 907.19 /2 = 50.4 mole
volume = 4 ft³ = 113.2 L
temperature = 40 F = 277.59 K
to find out
pressure of water
solution
we will apply here ideal gas condition
that is
PV = nRT .......................1
put here all value and here R = 0.0821 , T temperature and V volume and P pressure and n is no of mole
and we get here temperature
PV = nRT
2.04 × 113.2 = 50.4×0.0821×T
solve it and we get
T = 55.8 K
so we have given right chamber has twice the volume of the left chamber i.e
volume = twice of volume + volume
volume = 2(113.2) + 113.2
volume = 339.6 L
so from equation 1 pressure will be
PV = nRT
P(339.6) = 50.4 × ( 0.0821) × (277.59)
P = 3.3822 atm = 49.7 atm
so pressure of water will be 49.7 atm
Answer
given,
mass of the = m₁ = 8.75 Kg
another mass of the object = m₂ = 14 Kg
distance between them = 50 cm
R₁ = 17 cm
R₂ = 50 -17 = 33 cm
a) Force applied due to the Mass 8.75 in +ve x- direction
Force applied due to mass 14 Kg in -ve x-direction
net force
F = F₁ + F₂
Using newton second law
b) As the acceleration of mass comes out to be +ve hence, the direction will be toward the mass of 8.75 Kg
As per the question the wavelength of spectral line of the neutral hydrogen atom is 21 cm.
Spectral line of hydrogen atom will be observed when an electron will jump from higher excited to the ground state. If E is the energy of the ground state and E' is the energy of the higher excited state,the energy emitted when electron will jump from higher excited to ground state is E'-E.
As per Planck's quantum theory -
Where f is the frequency of emitted radiation and h is the Planck's constant.Actually this energy emitted is also electromagnetic in nature. We know that all the electromagnetic radiation will move with the same velocity which is equal to the velocity of light.
The velocity of light c= 3×10^8 m/s.Hence the velocity of wave corresponding to this spectral line is 3×10^8 m/s.
We know that velocity of a wave is the product of frequency and wavelength of that corresponding wave. Mathematically we can write it as-
[ is the wavelength of the wave ]
It is given that wavelength =21 cm=0.21 m
The frequency is calculated as -
Hence the antenna will be tuned to a frequency of 14.2857×10^8 Hz
Here Hertz[ Hz] is the unit of frequency.
Answer:
Increase Water Consumption
Try a New Diet
Help Your Cat Maintain a Healthy Weight
Increase Exercise and Enrichment
Minimize Stress and Anxiety
Add More Litter Boxes
Try Fiber or Probiotics
Ask Your Vet About Over-the-Counter Laxatives
Explanation:
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Hope this helps ;)</em></h2>
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