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2 years ago

A certain device in a 120-V circuit has a current rating of 20 A. What is the resistance of the device (how many ohms)?

Physics

1 answer:

Akimi4 [234]2 years ago

5 0

Answer:

R = 60 Ω

Explanation:

given,

Potential of the certain device, V = 120 V

current rating of the circuit, I = 20 A

resistance of the device, R = ?

Using Ohm's Law

V = I R

$R = \dfrac{V}{I}$

$R = \dfrac{120}{20}$

R = 60 Ω

hence, the resistance of the device is equal to 60 Ω

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A toaster draws 8 A of current with a voltage of 120 V. Which is the power used by the toaster?

dexar [7]

$U=120 \text{ V}\\
I=8\text{ A}\\
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P=120\cdot8=960 \text{ W}
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2 years ago

A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni

ad-work [718]

Answer:

The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

Explanation:

Given that,

Current $I = 2.60\hat{i}\ A$

Length = 0.750 m

Magnetic field $B = 1.50\hat{k}\ T$

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

$\vec{F}=l\vec{I}\times\vec{B}$

$\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}$

Since, $\hat{i}\times\hat{k}=-\hat{j}$

$\vec{F}=-2.925\hat{j}\ N$

Hence, The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

7 0

2 years ago

What are the three different types of friction

iogann1982 [59]

Answer:

sliding , static , rolling

Explanation:

HOPE IT WILL HELP YOU

5 0

2 years ago

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

jeyben [28]

Answer:

λ₁ = 2.50 10⁻² m, λ₂ = 1.66 10⁻² m

Explanation:

Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.

Let's calculate the wavelength for the two extreme frequencies of this band

wavelength and frequency are related

c = λ f

λ = c / f

f₁ = 12 GHz = 12 10⁹ Hz

λ₁ = 3 10⁸ /12 10⁹

λ₁ = 2.50 10⁻² m

f₂ = 18 GHz = 18 10⁹ Hz

λ₂ = 3 10⁸ /18 10⁹

λ₂ = 1.66 10⁻² m

Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures

8 0

2 years ago

Discuss the relationship between electric and magnetic fields. How are they related?

evablogger [386]

<span>Discuss the relationship between electric and magnetic fields. How are they related?</span>

The magnetic field is related to the electric field in such a way that magnetic fields moves perpendicular the electric field. This relationship exists between a magnetic field and an electric field is a consequence of associating elementary particles.

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4 0

2 years ago