6) John purchased 120 shares of Walmart stock at $58.02 each. He sold the stock for $120.98.

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

8 0

Answer:

John lost $6841.42.

Step-by-step explanation:

Let's find out how much John paid for the stock he bought. Each share cost $58.02. He bought 120 shares. Multiply the price by the number of shares.

58.02 x 120 = 6962.40

He sold the stock for $120.98 -- a huge loss! (We are not told that the $120.98 is the selling price of one share, so I'm assuming that's what John sold all his shares for.)

Find the difference to see what his loss was.

$6962.40 - $120.98 = $6841.42 LOST!

You might be interested in

Please help me with this

Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

$\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}$

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

$\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }$

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

$\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }$