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2 years ago

What is the GCF of 44j^5k^4 and 121j^2k^6?

Mathematics

2 answers:

Leviafan [203]2 years ago

7 0

$44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4$

vampirchik [111]2 years ago

7 0

44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

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Triangle STV has vertices S (-3, -2) , T (-4, 3) and V (-2, 3). If (x, y) arrow (x+2, y-3), what are the vertices of its image?

jeka94

Answer:

see below

Step-by-step explanation:

The mapping tells you how to find the vertices of the image:

(x, y) ⇒ (x +2, y -3)

S(-3,-2) ⇒ S'(-3 +2, -2 -3) = S'(-1, -5) . . . . . matches choice D

T(-4, 3) ⇒ T'(-4 +2, 3 -3) = T'(-2, 0)

V(-2, 3) ⇒ V'(-2 +2, 3 -3) = V'(0, 0)

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2 years ago

The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta

earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of k success in n samples drawn from a population of size N which include K success. Every draw is either a success of failure.

The random variable X = number of meals that will exceed the cost covered by the company.

The random variable X follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

$P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}$

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

$P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637$

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

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2 years ago

The sum of the digits of a two-digit number is 5. If the number is multiplied by 3, the result is 42. Write and solve a system o

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A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

"The sum of the digits is 5"
x + y = 5

The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

The number is: 10x + y
3(10x + y) = 42

The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42

Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

-3x - 3y = -15
30x + 3y = 42
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27x + 0 = 27
x = 1

then plug x = 1 into either equation to find y

1 + y = 5
y = 4

remember the x and y represent digits so the number xy is 14

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2 years ago

What is the simplified form of √144x^36

Nadusha1986 [10]

Answer:

The simplified form of $\sqrt{144x^{36}}$ is $12x^{18}$