there isnt a list of options given but should be something like
38 + 35 + 22 = 22 + 35 + 38
or maybe
38r + 35t + 22l = 22l + 35t + 38r
it equals 95
- Obtuse = one side is more than 90 degrees
- Acute = all sides are less than 90 degrees
- Isosceles = two sides are of the same length
- Equilateral triangle: all angles are of same measure (60)
- Scalene: all sides are of different lengths
- Right Triangle: One of the angles equals 90 degrees.
Hope this helps but if you got any other questions feel free to ask :) cause I suckeeeeddd at Geometry but I had to pass lolllll
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
Answer:
The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.
![Area = l * w](https://tex.z-dn.net/?f=Area%20%3D%20l%20%2A%20w)
![Area = 25\ cm * 15\ cm](https://tex.z-dn.net/?f=Area%20%3D%2025%5C%20cm%20%2A%2015%5C%20cm)
![Area = 375\ cm^2](https://tex.z-dn.net/?f=Area%20%3D%20375%5C%20cm%5E2)
The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.
![Area = l * w](https://tex.z-dn.net/?f=Area%20%3D%20l%20%2A%20w)
![Area = 25\ cm * 12\ cm](https://tex.z-dn.net/?f=Area%20%3D%2025%5C%20cm%20%2A%2012%5C%20cm)
![Area = 300\ cm^2](https://tex.z-dn.net/?f=Area%20%3D%20300%5C%20cm%5E2)
The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.
![Area = l * w](https://tex.z-dn.net/?f=Area%20%3D%20l%20%2A%20w)
![Area = 25\ cm * 9\ cm](https://tex.z-dn.net/?f=Area%20%3D%2025%5C%20cm%20%2A%209%5C%20cm)
![Area = 225\ cm^2](https://tex.z-dn.net/?f=Area%20%3D%20225%5C%20cm%5E2)
The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.
![Area = \frac{1}{2}* b*h](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%20b%2Ah)
![Area = \frac{1}{2}* 12\ cm*9\ cm](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%2012%5C%20cm%2A9%5C%20cm)
![Area = 54\ cm^2](https://tex.z-dn.net/?f=Area%20%3D%2054%5C%20cm%5E2)
Multiply it by two to get the area for both of the triangles.
![Area = 54\ cm^2 * 2](https://tex.z-dn.net/?f=Area%20%3D%2054%5C%20cm%5E2%20%2A%202)
![Area = 108\ cm^2](https://tex.z-dn.net/?f=Area%20%3D%20108%5C%20cm%5E2)
Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.
![Area_{total}=375\ cm^2 + 300\ cm^2 + 225\ cm^2 + 108\ cm^2](https://tex.z-dn.net/?f=Area_%7Btotal%7D%3D375%5C%20cm%5E2%20%2B%20300%5C%20cm%5E2%20%2B%20225%5C%20cm%5E2%20%2B%20108%5C%20cm%5E2)
![Area_{total}=1008\ cm^2](https://tex.z-dn.net/?f=Area_%7Btotal%7D%3D1008%5C%20cm%5E2)
Therefore, our final answer is option B, 1008 ![cm^2](https://tex.z-dn.net/?f=cm%5E2)
Hope this helps!