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2 years ago

The sizes in the above sequence make a geometric sequence. What is the ratio of the sequence?

Mathematics

1 answer:

svetlana [45]2 years ago

5 0

I dont know heelp
kkkkkkkkkk

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Slope is written as a ratio of the vertical change (run) to the horizontal change (rise) between any two points on a line.

hichkok12 [17]

Answer:

Step-by-step explanation:

Yeah the equation is change in y over change in x; change in is represented with the delta sign, so y2-y1/x2-x1

6 0

1 year ago

Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6

e-lub [12.9K]

Answer:

4.08%

Step-by-step explanation:

% error = error/actual length × 100

Error = 20.4-19.6

= 0.8

% error = 0.8/19.6 × 100

= 4.08%

8 0

2 years ago

The question is in the picture, please help.

Leto [7]

Answer:

how to understand the problem is picture the shape as a house and try to figure out what to do next

Step-by-step explanation:

8 0

2 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

2 years ago

Please help me out I need help so bad

wel

the answer is definitly C

5 0

3 years ago