Step-by-step explanation:
The answer is OPTION C
Find the Inverse of a 3x3 Matrix.
First
Find the Determinant of A(The coefficients of e
Proceed towards finding the CO FACTOR of the 3x3 Matrix.
+. - +
A= [ 1 -1 -1 ]
[ -1 2 3 ]
[ 1 1 4 ]
The determinant of this is 1.
Find the co factor
| 2 3 | |-1 3 | |-1 2 |
| 1. 4. | |1 4 | |1. 1 |
|-1. -1 | |1 -1 | |1 -1
| 1. 4 | |1. 4| |1 1|
|-1. -1 | |1 -1 | |1. -1
|2. 3| |-1. 3| |-1 2|
After Evaluating The Determinant of each 2x 2 Matrix
You'll have
[ 5 7 -3]
[3 5 -2 ]
[-1 -2 1]
Reflect this along the diagonal( Keep 5,5 -2)
Then switching positions of other value
No need of Multiplying by the determinant because its value is 1 from calculation.
After this
Our Inverse Matrix Would be
[ 5 3 -1 ]
[7 5 -2 ]
[ -3 -2 1]
THIS IS OUR INVERSE.
SO
OPTION C
Answer:
x and y can help you show you the constant rate or the unit rate
Step-by-step explanation:
if you use a graph you can see that x mutipley my a certain number gets you y
Answer:
Answer D: 12
Step-by-step explanation:
Three distinct denominators are shown here: 4, 3 and 2. The LCD is 12.
This corresponds to answer D.
A) Your primary concerns are the points B and E, so y> .5x+4 and y>or= x-4B) choose one or both points, and enter them into the equations. If the statements are true, then the equations work
for problem C So, any point in the shaded area, but not on the line, are valid points for Natalie's school
Use the equation
For A. The problem would be set up like so
5 _ -1
--------
4 _ -2
Start by subtracting 5 minus -1 which is 6 because minus a negative becomes a positive then subtract 4 minus -2 which is 6, remember minus a negative becomes a positive, then divide 6/6 to get 1
For B.
-5 _ -0
----------
3 _ -1
Again subtract -5 by -0 which no matter what will be -5. Then make -1 positive because it's a subtracted negative so it becomes 3+1 which gives you 4. Your answer is -5/4
If you need help with the rest message me good luck