Answer:
need more so we can answer
Explanation:
Answer:
1 mol of water is produced in those conditions.
Explanation:
The reaction to produce water between H₂ and O₂ is this:
2H₂ + O₂ → 2H₂O
We don't have the amount of hydrogen, so we have to think that is in excess.
Let's work with oxygen.
Ratio is 1:2
For 0.5 mole of oxygen, I will make the double of moles of water.
D. They act on a specific type of substrate in a reaction
Hope this helps!
Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.
Oxidation half-reaction: Zn + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-
Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻
Adding both reaction, we get the overall complete balanced equation:
<span>4Zn + NO</span>₃⁻ + 6 H₂O + 7 OH⁻ → 4 Zn(OH)₄²⁻ + NH₃
Thus, the charge in the product side is 4*-2 = <em>-8</em>.
