<span>2/18
1/9
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A dilation of factor k multiplies all lengths by k.
So, in your case, all lengths double. The new length is 4.
The equation of the line is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
Substituting values:
m = (8-4) / (6-2)
m = (4) / (4)
m = 1
Then, the equation is:
y-4 = 1 * (x-2)
Rewriting:
y = x-2 + 4
y = x + 2
The midpoint is:
k = ((x1 + x2) / 2, (y1 + y2) / 2)
k = ((2 + 6) / 2, (4 + 8) / 2)
k = ((8) / 2, (12) / 2)
k = (4, 6)
Then, the equation of the perpendicular line that passes through k is:
y = -x + b
Looking for b we have:
6 = -4 + b
b = 6 + 4
b = 10
Substituting:
y = -x + 10
Answer:
An equation of a line perpendicular to jl and passing through k is:
y = -x + 10
First expand the brackets 18x-12=22x and then you move the 18x to the other side so 12=22x-18x 12=4x. 3=x
9514 1404 393
Answer:
128 miles
Step-by-step explanation:
The convict has a head start of ...
distance = speed × time
distance = (8 mi/h) × (14 h) = 112 mi
That distance is being closed at a rate that is the difference between the speeds, so ...
64 mi/h -8 mi/h = 56 mi/h
The time it takes the guards to catch the convict will be ...
time = distance/speed
time = (112 mi)/(56 mi/h) = 2 h
The guards and prisoner will be at a distance from the prison of ...
distance = speed × time
distance = (64 mi/h)(2 h) = 128 mi
The convict will be caught 128 miles from the prison.
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<em>Check</em>
The convict will run an additional (8 mi/h)(2 h) = 16 mi after the guards start pursuit. That, in addition to the 112 miles already run, will total 112+16=128 miles, the same distance the guards travel in that 2 hours.