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2 years ago

Find the missing angle! Please add an explanation!

Mathematics

1 answer:

AlladinOne [14]2 years ago

6 0

Answer:

The answer is: $58^\circ$

Step-by-step explanation:

If we add the angles inside a triangle, we must have $180^\circ$ . So we have an $57^\circ$ angle and an $65^\circ$ angle, their sum is $122^\circ$ , so the missing angle must be $180^\circ-122^\circ=58^\circ$

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Stuck on this question. Help appreciated!!

marta [7]

Answer:

the missing is 4.98

Step-by-step explanation:

4 0

2 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

2 years ago

Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The

Viktor [21]

Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

10x + 8y = 210- - - - - - - - - - -1

The number of round chocolates is 3 less than twice the number of square chocolates. It means that

y = 2x - 3

Substituting y = 2x - 3 into equation 1, it becomes

10x + 8(2x - 3) = 210

10x + 16x - 24 = 210

26x = 210 + 24

26x = 234

x = 234/26

x = 9

y = 2x - 3 = 2 × 9 - 3

y = 18 - 3

y = 15

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2 years ago

BRAINLIEST ANSWER TO FIRST ANSWERER <br><br> What is the value of x?

grigory [225]

It's really simple

if a+95=180 you solve for a

a+95=180
-95 -95
a=85

a triangle in total is 180 degrees

now that you know two of the angles find x is really easy

you add 60+85

you get 145

you then subtract 180-145

and get 35 as the answer

x=35

3 0

2 years ago

Hi! plz help it would mean a lot ty! and plz don't troll! first person who solves it get brainlist!

Margaret [11]

Answer:

its b

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers