Answer: As x -> ♾, h(x) -> -♾, and as x -> -♾,h(x) -> -♾
Step-by-step explanation:
Using the slope - intercept relation, the required equation which models the scenario and Raul's speed are ;
- <em>y</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>7.5x</em><em> </em><em>+</em><em> </em><em>15</em><em> </em>
- <em>4</em><em> </em><em>miles</em><em> </em><em>per</em><em> </em><em>hour</em><em> </em>
Time difference, Δt = 1.2 hours - 0.5 hours = 0.7 hours
Change in distance, Δd = 11.25 - 6 = 5.25 miles
Assuming a constant speed :
- Speed = (Δd ÷ Δt) = (5.25 ÷ 0.7) = 7.5 mi/hr
<u>Using the general form</u> :
At, x = 1.2 hours ;
Miles left, y = 6 miles
End point decreases by 7.5 mi/hr (-7.5 mi/hr)
Inputting the data into the equation :
6 = - 7.5(1.2) + c
6 = - 9 + c
c = 6 + 9 = 15 miles
<u>The expression in slope intercept form becomes</u> ;
<u>If Raul lives 5 miles closer to the beach</u> ;
<u>Time it will take Luis to get to the beach</u> :
- Time taken = (15 ÷ 7.5) = 2.5 hours
Distance Raul has to cover = 15 - 5 = 10 miles
To reach the beach after 2.5 hours ;
- Speed required = (10 ÷ 2.5) = 4 mi/hr
Therefore, Raul has to ride at 4 miles per hour for the plan to work.
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Answer:
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Is there more information i can get out of this ?
The predicted value of hardness at 37 hours is 243.87 and an 85% confidence interval for the mean hardness is (242.12, 245.61). At 41 hours, the predicted hardness is 252 and an 85% confidence interval for mean hardness is (249.83, 254.18). The confidence interval for X is equals to 41 which is wider because the value 41 is farther away from the sample mean X than is 37. As an outcome, the standard error for the prediction is larger.