Answer:
Step-by-step explanation:
Let's first find the exponential function that models the situation in year one. The exponential standard form is
where a is the initial value and b is the growth/decay rate in decimal form. If it is growth it is added to 100% of the initial value; if it is decay it is taken away from 100% of the initial value. We are told that the number of cars in year one was 80 million, so
a = 80 (in millions)
If b is increasing by 10%, then we are adding that amount to the initial 100% we started with to give us 100% + 10% = 110% or, in decimal form, 1.1
The model for our situation is
where y is the number of cars after x years goes by. We want to find the difference between years 3 and 2, so we will use our model twice, replacing x with both a 2 and then a 3 and subtracting.
When x = 2:
and
y = 80(1.21) so
y = 96.8 million cars
When x = 3:
and
y = 80(1.331) so
y = 106.48 million cars
The difference between years 3 and 2 is
106.48 - 96.8 = 9.68 million cars
Answer:
5
Step-by-step explanation:
In order to do this, you plug the point C (5,6) and the point D (2,2) into the distance formula, which was provided below. x2-x1 is 3, and that squared is 9. y2-y1 is 4, and that squared in 16. When adding 9 and 16 together, you get 25. When taking the square root of 25, you get + or - 5, but since distance cannot be negative on the coordinate plane, you get 5.
Answer: Heyaa!
The Answer is 2x+2
Step-by-step explanation:
<em>Simplify the expression.</em>
<em />
<u>hopefully this helps you !</u>
<em />
- Matthew ~
Answer:
if I'm not wrong I think it's B
