2 years ago

Which of the following is not an equivalent expression to -12 - 7x?

Mathematics

1 answer:

Art [367]2 years ago

3 0

THE CORRECT ANSWER IS -7X+{-12}

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Can you help me with a question? What is the equation of the blue line?

Artist 52 [7]

Answer:

y = -x - 1

Step-by-step explanation:

y = mx + b

slope (m): Since the line is going downhill, the slope will be negative

slope = rise / run

slope = 1 / 1

slope = 1

m = -1

y - intercept (b): this when x = 0, the line is crossing the vertical line (y-axis)

b = -1

so y = mx + b is

b = -1, m = -1

y = (-1)x + (-1)

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1 year ago

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3/22 + -1/11 Add this fraction

Mashcka [7]

You need to use a common denominator. The least common denominator of 11 and 22 is 22.

3/22 + -1/11 = 3/22 + -2/22 = 3/22 - 2/22 = 1/22

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2 years ago

A boat travels 432km in 24 hours how far can it travel in 16 hours?

pickupchik [31]

The answer is 288 km!

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2 years ago

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

2 years ago

2:5 is how much out of 27

spayn [35]

13.5 is your answer, here u are

5 0

2 years ago