Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Answer:
Step-by-step explanation:
Answer:
y = 3 (4)^x
Step-by-step explanation:
quadruples means multiplies by 4
This equation is in the form
y = ab^x where a is the initial amount and b is the amount we multiply by
y = 3 (4)^x
For number 1 and 2 you are correct but I'm not sure for number 3
