Above a pressure of 200 atmospheres and at a temperature of 100 degrees Celsius, water is in gas phase.
2 answers:
Answer: The given statement is false.
Explanation:
When water is boiled at a pressure of 1 atm and temperature is 100 degree celsius then both liquid and vapor state of water exists in equilibrium.
But as the temperature reaches at more than 100 degree celsius then liquid state of water changes into vapor state.
But when above pressure of 200 atmospheres and at a temperature of 100 degrees Celsius water is heated then it will exist in liquid phase and not in vapor phase.
Therefore, we can conclude that the statement, above a pressure of 200 atmospheres and at a temperature of 100 degrees Celsius, water is in gas phase, is false.
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The large piece of jewelry that has a mass of 132.6 g and when is submerged in a graduated cylinder that initially contains 48.6 ml water and the volume increases to 61.2 ml once the piece of jewelry is submerged, has a density of: 10.523 g/ml
To solve this problem the formulas and the procedures that we have to use are:
- v = v(f)-v(i)
- d = m/v
Where:
- d= density
- m= mass
- v= volume
- v(f) = final volume
- v(i) = initial volume
Information about the problem:
- m = 132.6 g
- v(i) = 48.6 ml
- v(f) = 61.2 ml
- v = ?
- d =?
Applying the volume formula we get:
v = v(f)-v(i)
v = 61.2 ml - 48.6 ml
v = 12.6 ml
Applying the density formula we get:
d = m/v
d = 132.6 g/12.6 ml
d = 10.523 g/ml
<h3>What is density?</h3>It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
Learn more about density in: brainly.com/question/1354972
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Answer:
There was 450.068g of water in the pot.
Explanation:
Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L
Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s
Let m = x g be the weight of water in the pot.
Energy required to vaporise water = mL = 2260x
Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x
Total energy required =
Hence, there was 450.068g of water in the pot.