Answer:
Im not a 100% sure but my best guess would be the 3rd equation:
f(x) = (x - 1) (x + 3)
Please let me know if I was wrong, but i hope this helped you!
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C.
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
w=+/-4.24 or whatever could be either since its squared
Step-by-step explanation:
subtract 25 so 5x^2=90. divide by 5 so w^2=18 then square root to get rid of the ^2 so w=+/-4.24
Answer:
x = 10.8
Step-by-step explanation:
cos 26° = x/12
0.8988 = x/12
x = 10.785
Answer: 1,501
Step-by-step explanation:
100% = 1,580
100% - 5% lost
95%
1580 x .95 = 1501